9/2=(b-27)/18

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Solution for 9/2=(b-27)/18 equation: 



9/2=(b-27)/18

We move all terms to the left:

9/2-((b-27)/18)=0

We calculate fractions


(-((b-27)*2)/()+()/()=0



We calculate terms in parentheses: +(-((b-27)*2)/()+()/(), so:

-((b-27)*2)/()+()/(

We add all the numbers together, and all the variables

-((b-27)*2)/()+1

We multiply all the terms by the denominator


-((b-27)*2)+1*()



We calculate terms in parentheses: -((b-27)*2), so:

(b-27)*2

We multiply parentheses

2b-54

Back to the equation:

-(2b-54)



We add all the numbers together, and all the variables

-(2b-54)

We get rid of parentheses

-2b+54

Back to the equation:

+(-2b+54)



We get rid of parentheses

-2b+54=0

We move all terms containing b to the left, all other terms to the right

-2b=-54

b=-54/-2

b=+27

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