9/2b+11-5/6b=b+2

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Solution for 9/2b+11-5/6b=b+2 equation: 



9/2b+11-5/6b=b+2

We move all terms to the left:

9/2b+11-5/6b-(b+2)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R





Domain of the equation: 6b!=0

b!=0/6

b!=0

b∈R



We get rid of parentheses

9/2b-5/6b-b-2+11=0

We calculate fractions


-b+54b/12b^2+(-10b)/12b^2-2+11=0

We add all the numbers together, and all the variables

-1b+54b/12b^2+(-10b)/12b^2+9=0

We multiply all the terms by the denominator


-1b*12b^2+54b+(-10b)+9*12b^2=0

We add all the numbers together, and all the variables

54b-1b*12b^2+(-10b)+9*12b^2=0

Wy multiply elements

-12b^3+108b^2+54b+(-10b)=0

We get rid of parentheses

-12b^3+108b^2+54b-10b=0

We do not support ebpression: b^3

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