9/2k-2=2/k-8

Solution for 9/2k-2=2/k-8 equation:

D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

(9/2)*k-2 = 2/k-8 // - 2/k-8

(9/2)*k-(2/k)-2+8 = 0

(9/2)*k-2*k^-1-2+8 = 0

9/2*k^1-2*k^-1+6*k^0 = 0

(9/2*k^2+6*k^1-2*k^0)/(k^1) = 0 // * k^2

k^1*(9/2*k^2+6*k^1-2*k^0) = 0

k^1

(9/2)*k^2+6*k-2 = 0

(9/2)*k^2+6*k-2 = 0

DELTA = 6^2-(-2*4*(9/2))

DELTA = 72

DELTA > 0

k = (72^(1/2)-6)/(2*(9/2)) or k = (-72^(1/2)-6)/(2*(9/2))

k = (6*2^(1/2)-6)/9 or k = (-6*2^(1/2)-6)/9

k in { (-6*2^(1/2)-6)/9, (6*2^(1/2)-6)/9} 

k in { (-6*2^(1/2)-6)/9, (6*2^(1/2)-6)/9 }