9/2t+3/t=1

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Solution for 9/2t+3/t=1 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(9/2)*t+3/t = 1 // - 1

(9/2)*t+3/t-1 = 0

9/2*t^1+3*t^-1-1*t^0 = 0

(9/2*t^2-1*t^1+3*t^0)/(t^1) = 0 // * t^2

t^1*(9/2*t^2-1*t^1+3*t^0) = 0

t^1

(9/2)*t^2-t+3 = 0

(9/2)*t^2-t+3 = 0

DELTA = (-1)^2-(3*4*(9/2))

DELTA = -53

DELTA < 0

t in { } 

t belongs to the empty set

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