9/2x-3=5/x+5

Solution for 9/2x-3=5/x+5 equation:

9/2x-3=5/x+5

We move all terms to the left:

9/2x-3-(5/x+5)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x+5)!=0

x∈R


We get rid of parentheses

9/2x-5/x-5-3=0

We calculate fractions


9x/2x^2+(-10x)/2x^2-5-3=0

We add all the numbers together, and all the variables

9x/2x^2+(-10x)/2x^2-8=0

We multiply all the terms by the denominator


9x+(-10x)-8*2x^2=0

Wy multiply elements

-16x^2+9x+(-10x)=0

We get rid of parentheses

-16x^2+9x-10x=0

We add all the numbers together, and all the variables

-16x^2-1x=0

a = -16; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-16)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-16}=\frac{0}{-32}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-16}=\frac{2}{-32}
=-1/16
$