9/2x=10-8/x

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Solution for 9/2x=10-8/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(9/2)*x = 10-(8/x) // - 10-(8/x)

(9/2)*x+8/x-10 = 0

9/2*x^1+8*x^-1-10*x^0 = 0

(9/2*x^2-10*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(9/2*x^2-10*x^1+8*x^0) = 0

x^1

(9/2)*x^2-10*x+8 = 0

(9/2)*x^2-10*x+8 = 0

DELTA = (-10)^2-(4*8*(9/2))

DELTA = -44

DELTA < 0

x in { } 

x belongs to the empty set

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