9/3+8x2+x=20

Solution for 9/3+8x2+x=20 equation:

9/3+8x^2+x=20

We move all terms to the left:

9/3+8x^2+x-(20)=0

determiningTheFunctionDomain
8x^2+x-20+9/3=0

We add all the numbers together, and all the variables

8x^2+x-17=0

a = 8; b = 1; c = -17;
Δ = b2-4ac
Δ = 12-4·8·(-17)
Δ = 545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{545}}{2*8}=\frac{-1-\sqrt{545}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{545}}{2*8}=\frac{-1+\sqrt{545}}{16}
$