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9/4n+3/2n=15/8
We move all terms to the left:
9/4n+3/2n-(15/8)=0
Domain of the equation: 4n!=0
n!=0/4
n!=0
n∈R
Domain of the equation: 2n!=0We add all the numbers together, and all the variables
n!=0/2
n!=0
n∈R
9/4n+3/2n-(+15/8)=0
We get rid of parentheses
9/4n+3/2n-15/8=0
We calculate fractions
(-240n^2)/512n^2+1152n/512n^2+768n/512n^2=0
We multiply all the terms by the denominator
(-240n^2)+1152n+768n=0
We add all the numbers together, and all the variables
(-240n^2)+1920n=0
We get rid of parentheses
-240n^2+1920n=0
a = -240; b = 1920; c = 0;
Δ = b2-4ac
Δ = 19202-4·(-240)·0
Δ = 3686400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3686400}=1920$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1920)-1920}{2*-240}=\frac{-3840}{-480} =+8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1920)+1920}{2*-240}=\frac{0}{-480} =0 $
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