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9/4x+1/2x=44
We move all terms to the left:
9/4x+1/2x-(44)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
18x/8x^2+4x/8x^2-44=0
We multiply all the terms by the denominator
18x+4x-44*8x^2=0
We add all the numbers together, and all the variables
22x-44*8x^2=0
Wy multiply elements
-352x^2+22x=0
a = -352; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-352)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-352}=\frac{-44}{-704} =1/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-352}=\frac{0}{-704} =0 $
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