9/4x=y+5/2;0=-2x-10+2y

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Solution for 9/4x=y+5/2;0=-2x-10+2y system of equations: 


  • /| (9/4)*x-y-(5/2) = 0| 0-(-2*x)-(2*y)+10 = 0
  • We try to solve the equation: (9/4)*x-y-(5/2) = 0
  • 9/4*x-y-5/2 = 0 // - 9/4*x-5/2
  • -y = -(9/4*x-5/2) // * -1
  • y = 9/4*x-5/2
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 0-(2*(9/4*x-5/2))-(-2*x)+10 = 0| y = 9/4*x-5/2
  • 2*x-1*2*(9/4*x-5/2)+0+10 = 0
  • 5-5/2*x+10 = 0
  • 15-5/2*x = 0
  • 15-5/2*x = 0 // - 15
  • -5/2*x = -15 // : -5/2
  • x = -15/(-5/2)
  • x = 6
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 9/4*x-5/2: 
  • y = 9/4*6-5/2
  • y = 27/2-5/2
  • y = 11
  • We get a system of equations:
  • /| y = 11| x = 6

 

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