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9/5(10x-5)=5/3(6x-9)
We move all terms to the left:
9/5(10x-5)-(5/3(6x-9))=0
Domain of the equation: 5(10x-5)!=0
x∈R
Domain of the equation: 3(6x-9))!=0We calculate fractions
x∈R
(27x6/(5(10x-5)*3(6x-9)))+(-25x1/(5(10x-5)*3(6x-9)))=0
We calculate terms in parentheses: +(27x6/(5(10x-5)*3(6x-9))), so:
27x6/(5(10x-5)*3(6x-9))
We multiply all the terms by the denominator
27x6
We add all the numbers together, and all the variables
27x^6
We do not support expression: x^6
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