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9/5(x+2)=3x=12
We move all terms to the left:
9/5(x+2)-(3x)=0
Domain of the equation: 5(x+2)!=0We add all the numbers together, and all the variables
x∈R
-3x+9/5(x+2)=0
We multiply all the terms by the denominator
-3x*5(x+2)+9=0
Wy multiply elements
-15x^2(x+9=0
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