9/5(y+3)=40

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Solution for 9/5(y+3)=40 equation: 



9/5(y+3)=40

We move all terms to the left:

9/5(y+3)-(40)=0



Domain of the equation: 5(y+3)!=0

y∈R



We multiply all the terms by the denominator


-40*5(y+3)+9=0

Wy multiply elements

-200y(y+9=0

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