9/5+3/5x=29/10+7/2x+1/2

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Solution for 9/5+3/5x=29/10+7/2x+1/2 equation: 


x in (-oo:+oo)

(3/5)*x+9/5 = (7/2)*x+29/10+1/2 // - (7/2)*x+29/10+1/2

(3/5)*x-((7/2)*x)+9/5-(29/10)-(1/2) = 0

(3/5)*x+(-7/2)*x+9/5-29/10-1/2 = 0

-29/10*x-8/5 = 0 // + 8/5

-29/10*x = 8/5 // : -29/10

x = 8/5/(-29/10)

x = -16/29

x = -16/29

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