9/5c+32=40

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Solution for 9/5c+32=40 equation: 



9/5c+32=40

We move all terms to the left:

9/5c+32-(40)=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We add all the numbers together, and all the variables

9/5c-8=0

We multiply all the terms by the denominator


-8*5c+9=0

Wy multiply elements

-40c+9=0

We move all terms containing c to the left, all other terms to the right

-40c=-9

c=-9/-40

c=9/40

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