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9/5c+32=41
We move all terms to the left:
9/5c+32-(41)=0
Domain of the equation: 5c!=0We add all the numbers together, and all the variables
c!=0/5
c!=0
c∈R
9/5c-9=0
We multiply all the terms by the denominator
-9*5c+9=0
Wy multiply elements
-45c+9=0
We move all terms containing c to the left, all other terms to the right
-45c=-9
c=-9/-45
c=1/5
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