9/5m+8=2/m

Solution for 9/5m+8=2/m equation:

9/5m+8=2/m

We move all terms to the left:

9/5m+8-(2/m)=0


Domain of the equation: 5m!=0

m!=0/5

m!=0

m∈R



Domain of the equation: m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

9/5m-(+2/m)+8=0

We get rid of parentheses

9/5m-2/m+8=0

We calculate fractions


9m/5m^2+(-10m)/5m^2+8=0

We multiply all the terms by the denominator


9m+(-10m)+8*5m^2=0

Wy multiply elements

40m^2+9m+(-10m)=0

We get rid of parentheses

40m^2+9m-10m=0

We add all the numbers together, and all the variables

40m^2-1m=0

a = 40; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·40·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*40}=\frac{0}{80}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*40}=\frac{2}{80}
=1/40
$