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9/5x+2x=1
We move all terms to the left:
9/5x+2x-(1)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2x+9/5x-1=0
We multiply all the terms by the denominator
2x*5x-1*5x+9=0
Wy multiply elements
10x^2-5x+9=0
a = 10; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·10·9
Δ = -335
Delta is less than zero, so there is no solution for the equation
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