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9/5x+5=x+8.
We move all terms to the left:
9/5x+5-(x+8.)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
9/5x-(x+8)+5=0
We get rid of parentheses
9/5x-x-8+5=0
We multiply all the terms by the denominator
-x*5x-8*5x+5*5x+9=0
Wy multiply elements
-5x^2-40x+25x+9=0
We add all the numbers together, and all the variables
-5x^2-15x+9=0
a = -5; b = -15; c = +9;
Δ = b2-4ac
Δ = -152-4·(-5)·9
Δ = 405
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{405}=\sqrt{81*5}=\sqrt{81}*\sqrt{5}=9\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-9\sqrt{5}}{2*-5}=\frac{15-9\sqrt{5}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+9\sqrt{5}}{2*-5}=\frac{15+9\sqrt{5}}{-10} $
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