9/5x-4=3/2x

Solution for 9/5x-4=3/2x equation:

9/5x-4=3/2x

We move all terms to the left:

9/5x-4-(3/2x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

9/5x-(+3/2x)-4=0

We get rid of parentheses

9/5x-3/2x-4=0

We calculate fractions


18x/10x^2+(-15x)/10x^2-4=0

We multiply all the terms by the denominator


18x+(-15x)-4*10x^2=0

Wy multiply elements

-40x^2+18x+(-15x)=0

We get rid of parentheses

-40x^2+18x-15x=0

We add all the numbers together, and all the variables

-40x^2+3x=0

a = -40; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-40)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-40}=\frac{-6}{-80}
=3/40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-40}=\frac{0}{-80}
=0
$