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9/64=p2
We move all terms to the left:
9/64-(p2)=0
We add all the numbers together, and all the variables
-1p^2+9/64=0
We multiply all the terms by the denominator
-1p^2*64+9=0
Wy multiply elements
-64p^2+9=0
a = -64; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-64)·9
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-64}=\frac{-48}{-128} =3/8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-64}=\frac{48}{-128} =-3/8 $
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