9/6=(2a+3)/2

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Solution for 9/6=(2a+3)/2 equation: 



9/6=(2a+3)/2

We move all terms to the left:

9/6-((2a+3)/2)=0

We calculate fractions


(-((2a+3)*6)/()+()/()=0



We calculate terms in parentheses: +(-((2a+3)*6)/()+()/(), so:

-((2a+3)*6)/()+()/(

We add all the numbers together, and all the variables

-((2a+3)*6)/()+1

We multiply all the terms by the denominator


-((2a+3)*6)+1*()



We calculate terms in parentheses: -((2a+3)*6), so:

(2a+3)*6

We multiply parentheses

12a+18

Back to the equation:

-(12a+18)



We add all the numbers together, and all the variables

-(12a+18)

We get rid of parentheses

-12a-18

Back to the equation:

+(-12a-18)



We get rid of parentheses

-12a-18=0

We move all terms containing a to the left, all other terms to the right

-12a=18

a=18/-12

a=-1+1/2

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