9/7(1+x)-6/7x+1=1

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Solution for 9/7(1+x)-6/7x+1=1 equation:



9/7(1+x)-6/7x+1=1
We move all terms to the left:
9/7(1+x)-6/7x+1-(1)=0
Domain of the equation: 7(1+x)!=0
x∈R
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
We add all the numbers together, and all the variables
9/7(x+1)-6/7x+1-1=0
We add all the numbers together, and all the variables
9/7(x+1)-6/7x=0
We calculate fractions
63x/(49x^2+49x)+(-42xx/(49x^2+49x)=0
We calculate terms in parentheses: +(-42xx/(49x^2+49x), so:
-42xx/(49x^2+49x
We multiply all the terms by the denominator
-42xx
Back to the equation:
+(-42xx)
We get rid of parentheses
63x/(49x^2+49x)-42xx=0
We multiply all the terms by the denominator
63x-42xx*(49x^2+49x)=0
We multiply parentheses
-2058x^3-2058x^2+63x=0
We do not support expression: x^3

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