9/7(a+3)=4+5/4a

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Solution for 9/7(a+3)=4+5/4a equation: 



9/7(a+3)=4+5/4a

We move all terms to the left:

9/7(a+3)-(4+5/4a)=0



Domain of the equation: 7(a+3)!=0

a∈R





Domain of the equation: 4a)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

9/7(a+3)-(5/4a+4)=0

We get rid of parentheses

9/7(a+3)-5/4a-4=0

We calculate fractions


36a/(28a^2+84a)+(-35aa/(28a^2+84a)-4=0

We calculate fractions

We do not support eapression: a^3

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