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9/7x=13/14x+2
We move all terms to the left:
9/7x-(13/14x+2)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 14x+2)!=0We get rid of parentheses
x∈R
9/7x-13/14x-2=0
We calculate fractions
126x/98x^2+(-91x)/98x^2-2=0
We multiply all the terms by the denominator
126x+(-91x)-2*98x^2=0
Wy multiply elements
-196x^2+126x+(-91x)=0
We get rid of parentheses
-196x^2+126x-91x=0
We add all the numbers together, and all the variables
-196x^2+35x=0
a = -196; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-196)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-196}=\frac{-70}{-392} =5/28 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-196}=\frac{0}{-392} =0 $
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