9/a-3/4a=1

Solution for 9/a-3/4a=1 equation:

9/a-3/4a=1

We move all terms to the left:

9/a-3/4a-(1)=0


Domain of the equation: a!=0

a∈R



Domain of the equation: 4a!=0

a!=0/4

a!=0

a∈R


We calculate fractions


36a/4a^2+(-3a)/4a^2-1=0

We multiply all the terms by the denominator


36a+(-3a)-1*4a^2=0

Wy multiply elements

-4a^2+36a+(-3a)=0

We get rid of parentheses

-4a^2+36a-3a=0

We add all the numbers together, and all the variables

-4a^2+33a=0

a = -4; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·(-4)·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*-4}=\frac{-66}{-8}
=8+1/4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*-4}=\frac{0}{-8}
=0
$