9/b-3/b

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Solution for 9/b-3/b equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

9/b-(3/b) = 0

9/b-3*b^-1 = 0

6*b^-1 = 0 // : 6

b^-1 = 0

b należy do O

b belongs to the empty set

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