9/k-8=10/(3k)-4

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Solution for 9/k-8=10/(3k)-4 equation: 


D( k )

3*k = 0

k = 0

3*k = 0

3*k = 0

3*k = 0 // : 3

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

9/k-8 = 10/(3*k)-4 // - 10/(3*k)-4

9/k-(10/(3*k))-8+4 = 0

9/k+(-10/3)*k^-1-8+4 = 0

17/3*k^-1 = 4 // : 17/3

k^-1 = 12/17

-1 < 0

1/(k^1) = 12/17 // * k^1

1 = 12/17*k^1 // : 12/17

17/12 = k^1

k = 17/12

k = 17/12

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