9/m-3/2m=15/m

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Solution for 9/m-3/2m=15/m equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

9/m-((3/2)*m) = 15/m // - 15/m

9/m-((3/2)*m)-(15/m) = 0

(-3/2)*m+9/m-15*m^-1 = 0

-3/2*m^1-6*m^-1 = 0

(-3/2*m^2-6*m^0)/(m^1) = 0 // * m^2

m^1*(-3/2*m^2-6*m^0) = 0

m^1

(-3/2)*m^2-6 = 0

(-3/2)*m^2-6 = 0

DELTA = 0^2-(-6*4*(-3/2))

DELTA = -36

DELTA < 0

m in { } 

m belongs to the empty set

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