9/x+4/6x-3

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Solution for 9/x+4/6x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/6)*x+9/x-3 = 0

2/3*x^1+9*x^-1-3*x^0 = 0

(2/3*x^2-3*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(2/3*x^2-3*x^1+9*x^0) = 0

x^1

(2/3)*x^2-3*x+9 = 0

(2/3)*x^2-3*x+9 = 0

DELTA = (-3)^2-(4*9*(2/3))

DELTA = -15

DELTA < 0

x in { } 

x belongs to the empty set

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