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9/x-3=7x-5
We move all terms to the left:
9/x-3-(7x-5)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
9/x-7x+5-3=0
We multiply all the terms by the denominator
-7x*x+5*x-3*x+9=0
We add all the numbers together, and all the variables
2x-7x*x+9=0
Wy multiply elements
-7x^2+2x+9=0
a = -7; b = 2; c = +9;
Δ = b2-4ac
Δ = 22-4·(-7)·9
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-16}{2*-7}=\frac{-18}{-14} =1+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+16}{2*-7}=\frac{14}{-14} =-1 $
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