9/x-x/3=2

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Solution for 9/x-x/3=2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

9/x-(x/3) = 2 // - 2

9/x-(x/3)-2 = 0

9*x^-1-1/3*x^1-2*x^0 = 0

(9*x^0-1/3*x^2-2*x^1)/(x^1) = 0 // * x^2

x^1*(9*x^0-1/3*x^2-2*x^1) = 0

x^1

(-1/3)*x^2-2*x+9 = 0

(-1/3)*x^2-2*x+9 = 0

DELTA = (-2)^2-(4*9*(-1/3))

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(2*(-1/3)) or x = (2-16^(1/2))/(2*(-1/3))

x = -9 or x = 3

x in { -9, 3} 

x in { -9, 3 }

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