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9/x=11/3x-8
We move all terms to the left:
9/x-(11/3x-8)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x-8)!=0We get rid of parentheses
x∈R
9/x-11/3x+8=0
We calculate fractions
27x/3x^2+(-11x)/3x^2+8=0
We multiply all the terms by the denominator
27x+(-11x)+8*3x^2=0
Wy multiply elements
24x^2+27x+(-11x)=0
We get rid of parentheses
24x^2+27x-11x=0
We add all the numbers together, and all the variables
24x^2+16x=0
a = 24; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·24·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*24}=\frac{-32}{48} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*24}=\frac{0}{48} =0 $
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