9/z+9/2z=2

Solution for 9/z+9/2z=2 equation:

9/z+9/2z=2

We move all terms to the left:

9/z+9/2z-(2)=0


Domain of the equation: z!=0

z∈R



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R


We calculate fractions


18z/2z^2+9z/2z^2-2=0

We multiply all the terms by the denominator


18z+9z-2*2z^2=0

We add all the numbers together, and all the variables

27z-2*2z^2=0

Wy multiply elements

-4z^2+27z=0

a = -4; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-4)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-4}=\frac{-54}{-8}
=6+3/4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-4}=\frac{0}{-8}
=0
$