90+(2x=40)+(3x-10)=180

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Solution for 90+(2x=40)+(3x-10)=180 equation: 



90+(2x=40)+(3x-10)=180

We move all terms to the left:

90+(2x-(40)+(3x-10))=0



We calculate terms in parentheses: +(2x-40+(3x-10)), so:

2x-40+(3x-10)

determiningTheFunctionDomain
2x+(3x-10)-40

We get rid of parentheses

2x+3x-10-40

We add all the numbers together, and all the variables

5x-50

Back to the equation:

+(5x-50)



We get rid of parentheses

5x-50+90=0

We add all the numbers together, and all the variables

5x+40=0

We move all terms containing x to the left, all other terms to the right

5x=-40

x=-40/5

x=-8

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