90-(12x-5)=(4x+15)

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Solution for 90-(12x-5)=(4x+15) equation: 



90-(12x-5)=(4x+15)

We move all terms to the left:

90-(12x-5)-((4x+15))=0

We get rid of parentheses

-12x-((4x+15))+5+90=0



We calculate terms in parentheses: -((4x+15)), so:

(4x+15)

We get rid of parentheses

4x+15

Back to the equation:

-(4x+15)



We add all the numbers together, and all the variables

-12x-(4x+15)+95=0

We get rid of parentheses

-12x-4x-15+95=0

We add all the numbers together, and all the variables

-16x+80=0

We move all terms containing x to the left, all other terms to the right

-16x=-80

x=-80/-16

x=+5

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