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90.75=3n^2
We move all terms to the left:
90.75-(3n^2)=0
a = -3; b = 0; c = +90.75;
Δ = b2-4ac
Δ = 02-4·(-3)·90.75
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-33}{2*-3}=\frac{-33}{-6} =5+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+33}{2*-3}=\frac{33}{-6} =-5+1/2 $
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