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900=3.14r^2
We move all terms to the left:
900-(3.14r^2)=0
We get rid of parentheses
-3.14r^2+900=0
a = -3.14; b = 0; c = +900;
Δ = b2-4ac
Δ = 02-4·(-3.14)·900
Δ = 11304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11304}=\sqrt{36*314}=\sqrt{36}*\sqrt{314}=6\sqrt{314}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{314}}{2*-3.14}=\frac{0-6\sqrt{314}}{-6.28} =-\frac{6\sqrt{314}}{-6.28} =-\frac{\sqrt{314}}{-1.04666666667} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{314}}{2*-3.14}=\frac{0+6\sqrt{314}}{-6.28} =\frac{6\sqrt{314}}{-6.28} =\frac{\sqrt{314}}{-1.04666666667} $
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