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90=(6x)(x+13)
We move all terms to the left:
90-((6x)(x+13))=0
We calculate terms in parentheses: -(6x(x+13)), so:We get rid of parentheses
6x(x+13)
We multiply parentheses
6x^2+78x
Back to the equation:
-(6x^2+78x)
-6x^2-78x+90=0
a = -6; b = -78; c = +90;
Δ = b2-4ac
Δ = -782-4·(-6)·90
Δ = 8244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8244}=\sqrt{36*229}=\sqrt{36}*\sqrt{229}=6\sqrt{229}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-6\sqrt{229}}{2*-6}=\frac{78-6\sqrt{229}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+6\sqrt{229}}{2*-6}=\frac{78+6\sqrt{229}}{-12} $
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