90=15(b+2)+15+(2b-9)+b

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Solution for 90=15(b+2)+15+(2b-9)+b equation: 



90=15(b+2)+15+(2b-9)+b

We move all terms to the left:

90-(15(b+2)+15+(2b-9)+b)=0



We calculate terms in parentheses: -(15(b+2)+15+(2b-9)+b), so:

15(b+2)+15+(2b-9)+b

determiningTheFunctionDomain
15(b+2)+(2b-9)+b+15

We add all the numbers together, and all the variables

b+15(b+2)+(2b-9)+15

We multiply parentheses

b+15b+(2b-9)+30+15

We get rid of parentheses

b+15b+2b-9+30+15

We add all the numbers together, and all the variables

18b+36

Back to the equation:

-(18b+36)



We get rid of parentheses

-18b-36+90=0

We add all the numbers together, and all the variables

-18b+54=0

We move all terms containing b to the left, all other terms to the right

-18b=-54

b=-54/-18

b=+3

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