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90=5x(2x-30)
We move all terms to the left:
90-(5x(2x-30))=0
We calculate terms in parentheses: -(5x(2x-30)), so:We get rid of parentheses
5x(2x-30)
We multiply parentheses
10x^2-150x
Back to the equation:
-(10x^2-150x)
-10x^2+150x+90=0
a = -10; b = 150; c = +90;
Δ = b2-4ac
Δ = 1502-4·(-10)·90
Δ = 26100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{26100}=\sqrt{900*29}=\sqrt{900}*\sqrt{29}=30\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-30\sqrt{29}}{2*-10}=\frac{-150-30\sqrt{29}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+30\sqrt{29}}{2*-10}=\frac{-150+30\sqrt{29}}{-20} $
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