90=a+a+9+(9+a)/2+2a

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Solution for 90=a+a+9+(9+a)/2+2a equation: 



90=a+a+9+(9+a)/2+2a

We move all terms to the left:

90-(a+a+9+(9+a)/2+2a)=0



Domain of the equation: 2+2a)!=0

We move all terms containing a to the left, all other terms to the right

2a)!=-2

a!=-2/1

a!=-2

a∈R



We add all the numbers together, and all the variables

-(a+a+9+(a+9)/2+2a)+90=0

We multiply all the terms by the denominator


-(a+a+9+(a+9)+90*2+2a)=0



We calculate terms in parentheses: -(a+a+9+(a+9)+90*2+2a), so:

a+a+9+(a+9)+90*2+2a

determiningTheFunctionDomain
a+a+(a+9)+2a+9+90*2

We add all the numbers together, and all the variables

4a+(a+9)+189

We get rid of parentheses

4a+a+9+189

We add all the numbers together, and all the variables

5a+198

Back to the equation:

-(5a+198)



We get rid of parentheses

-5a-198=0

We move all terms containing a to the left, all other terms to the right

-5a=198

a=198/-5

a=-39+3/5

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