90x2+x+4x-10=360

Solution for 90x2+x+4x-10=360 equation:

90x^2+x+4x-10=360

We move all terms to the left:

90x^2+x+4x-10-(360)=0

We add all the numbers together, and all the variables

90x^2+5x-370=0

a = 90; b = 5; c = -370;
Δ = b2-4ac
Δ = 52-4·90·(-370)
Δ = 133225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{133225}=365$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-365}{2*90}=\frac{-370}{180}
=-2+1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+365}{2*90}=\frac{360}{180}
=2
$