92-2(3x-5)=10(2x-8)

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Solution for 92-2(3x-5)=10(2x-8) equation:



92-2(3x-5)=10(2x-8)
We move all terms to the left:
92-2(3x-5)-(10(2x-8))=0
We multiply parentheses
-6x-(10(2x-8))+10+92=0
We calculate terms in parentheses: -(10(2x-8)), so:
10(2x-8)
We multiply parentheses
20x-80
Back to the equation:
-(20x-80)
We add all the numbers together, and all the variables
-6x-(20x-80)+102=0
We get rid of parentheses
-6x-20x+80+102=0
We add all the numbers together, and all the variables
-26x+182=0
We move all terms containing x to the left, all other terms to the right
-26x=-182
x=-182/-26
x=+7

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