92-2(3x-5)=10(2x-8)

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Solution for 92-2(3x-5)=10(2x-8) equation: 



92-2(3x-5)=10(2x-8)

We move all terms to the left:

92-2(3x-5)-(10(2x-8))=0

We multiply parentheses

-6x-(10(2x-8))+10+92=0



We calculate terms in parentheses: -(10(2x-8)), so:

10(2x-8)

We multiply parentheses

20x-80

Back to the equation:

-(20x-80)



We add all the numbers together, and all the variables

-6x-(20x-80)+102=0

We get rid of parentheses

-6x-20x+80+102=0

We add all the numbers together, and all the variables

-26x+182=0

We move all terms containing x to the left, all other terms to the right

-26x=-182

x=-182/-26

x=+7

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