92x+1=(81x-2)/3x.

Solution for 92x+1=(81x-2)/3x. equation:

92x+1=(81x-2)/3x.

We move all terms to the left:

92x+1-((81x-2)/3x.)=0


Domain of the equation: 3x.)!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


92x*3x.)-((81x-2)+1*3x.)=0

Wy multiply elements

276x^2+3x=0

a = 276; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·276·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*276}=\frac{-6}{552}
=-1/92
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*276}=\frac{0}{552}
=0
$