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93=5-2(p-8)4p
We move all terms to the left:
93-(5-2(p-8)4p)=0
We calculate terms in parentheses: -(5-2(p-8)4p), so:We get rid of parentheses
5-2(p-8)4p
determiningTheFunctionDomain -2(p-8)4p+5
We multiply parentheses
-8p^2+64p+5
Back to the equation:
-(-8p^2+64p+5)
8p^2-64p-5+93=0
We add all the numbers together, and all the variables
8p^2-64p+88=0
a = 8; b = -64; c = +88;
Δ = b2-4ac
Δ = -642-4·8·88
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-16\sqrt{5}}{2*8}=\frac{64-16\sqrt{5}}{16} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+16\sqrt{5}}{2*8}=\frac{64+16\sqrt{5}}{16} $
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