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948x^2+62x-88=0
a = 948; b = 62; c = -88;
Δ = b2-4ac
Δ = 622-4·948·(-88)
Δ = 337540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{337540}=\sqrt{4*84385}=\sqrt{4}*\sqrt{84385}=2\sqrt{84385}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{84385}}{2*948}=\frac{-62-2\sqrt{84385}}{1896} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{84385}}{2*948}=\frac{-62+2\sqrt{84385}}{1896} $
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