94=5/9(x-32)

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Solution for 94=5/9(x-32) equation:



94=5/9(x-32)
We move all terms to the left:
94-(5/9(x-32))=0
Domain of the equation: 9(x-32))!=0
x∈R
We multiply all the terms by the denominator
-(5+94*9(x-32))=0
We calculate terms in parentheses: -(5+94*9(x-32)), so:
5+94*9(x-32)
determiningTheFunctionDomain 94*9(x-32)+5
Wy multiply elements
846x(x+5
Back to the equation:
-(846x(x+5)
We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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We calculate terms in parentheses: -(846x(x+5), so:
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