95=(9/5)c+32

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Solution for 95=(9/5)c+32 equation: 



95=(9/5)c+32

We move all terms to the left:

95-((9/5)c+32)=0



Domain of the equation: 5)c+32)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-((+9/5)c+32)+95=0

We multiply all the terms by the denominator


-((+9+95*5)c+32)=0



We calculate terms in parentheses: -((+9+95*5)c+32), so:

(+9+95*5)c+32

We add all the numbers together, and all the variables

484c+32

Back to the equation:

-(484c+32)



We get rid of parentheses

-484c-32=0

We move all terms containing c to the left, all other terms to the right

-484c=32

c=32/-484

c=-8/121

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