If it's not what You are looking for type in the equation solver your own equation and let us solve it.
95x+(5x-12)(x+7)=180
We move all terms to the left:
95x+(5x-12)(x+7)-(180)=0
We multiply parentheses ..
(+5x^2+35x-12x-84)+95x-180=0
We get rid of parentheses
5x^2+35x-12x+95x-84-180=0
We add all the numbers together, and all the variables
5x^2+118x-264=0
a = 5; b = 118; c = -264;
Δ = b2-4ac
Δ = 1182-4·5·(-264)
Δ = 19204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19204}=\sqrt{4*4801}=\sqrt{4}*\sqrt{4801}=2\sqrt{4801}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(118)-2\sqrt{4801}}{2*5}=\frac{-118-2\sqrt{4801}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(118)+2\sqrt{4801}}{2*5}=\frac{-118+2\sqrt{4801}}{10} $
| A(x)=-2x2+36x | | 12n+14=-10n-2 | | |-9+k|=18 | | 34x−18=14x−4 | | Y=64y-5 | | 12n+14=14 | | -4-5=2-(q+3) | | -33-12x=-9x+69 | | b2=29 | | n/3-5=12. | | 13x−14=9x+10 | | 11+3yy=8 | | 6x-192=-8x+60 | | 1.9x+5=1.5x+7 | | d2=49 | | 2+7a–18= | | -14x-30=18+2x | | 7(8)+12=9y-77 | | n+6=-1+2n | | 11d−10d+–4d=–18 | | (x−4)^2=9. | | -3q+27=-5q+25 | | 4(r+2)=0.2(20r+400) | | -11w+15w—5=15 | | 4(r+2)=1/5(20r+400) | | 24x+6=102 | | h/5h+2(11-h)=-5 | | f(6)=(6-3)/(8-6) | | f(-2)=((-2)-3)/(8-(-2)) | | 15x²-10x=5x | | 3x+8+2x+20=68 | | -(z+6)=-3 |